合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

        代寫COMP30026、C++設計程序代做
        代寫COMP30026、C++設計程序代做

        時間:2024-08-29  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



        Assignment 1
        COMP30026 Models of Computation
        School of Computing and Information Systems
        Due: Friday 30 August at 8:00pm
        Aims
        To improve your understanding of propositional logic and first-order predicate
        logic, including their use in mechanised reasoning; to develop your skills in
        analysis and formal reasoning about complex concepts, and to practise writing
        down formal arguments with clarity.
        Marking
        Each question is worth 2 marks, for a total of 12. We aim to ensure that
        anyone with a basic comprehension of the subject matter receives a passing
        mark. Getting full marks is intended to be considerably more difficult; the
        harder questions provide an opportunity for students to distinguish themselves.
        Your answers will be marked on correctness and clarity. Do not leave us
        guessing! It is better to be clear and wrong; vague answers will attract few
        if any marks. This also means you must show your working in mechanical
        questions!
        Finally, make sure your writing is legible! We cannot mark what we cannot
        read. (Keep in mind that the exam will be on paper, so this will be even more
        important later!)
        Academic Integrity
        In this assignment, individual work is called for. By submitting work for
        assessment you declare that:
        1. You understand the University  s policy on academic integrity.
        2. The work submitted is your original work.
        3. You have not been unduly assisted by any other person or third party.
        4. You have not unduly assisted anyone else.
        5. You have not used any unauthorized materials, including but not limited
        to AI and translation software.
        1
        However, if you get stuck, you can use the discussion board to ask any ques-
        tions you have. If your question reveals anything about your approach or work-
        ing, please make sure that it is set to   private  .
        You may only discuss the assignment in basic terms with your peers (e.g.
        clarifying what the question is asking, or recommending useful exercises). You
        may not directly help others in solving these problems, even by suggesting
        strategies.
        Soliciting or accepting further help from non-staff is cheating and will lead
        to disciplinary action.
        Q1 Propositional Logic: Island Puzzle
        You come across three inhabitants of the Island of Knights and Knaves. Now, a
        mimic has eaten one of them and stolen their appearance, as well as their status
        as a knight or knave. (And is thus bound by the same rules. Remember that
        knights always tell the truth, and knaves always lie!)
        Each makes a statement:
        1. A says:   C is either the mimic or a knight, or both.  
        2. B says:   It is not the case that both A is the mimic and C is a knave.  
        3. C says:   If B is a knight, then the mimic is a knave.  
        Task A
        Translate the information above into propositional formulas. Give an appropri-
        ate interpretation of all propositional letters used. Use the same interpretation
        throughout the question; do not give multiple interpretations.
        Task B
        Determine which of , , and is the mimic, and prove that it must be the
        case using an informal argument.
        Some advice: A good answer should not be much longer than about 250
        words. But do not worry about the length of your first draft! Instead focus on
        finding a proof in the first place. Once you have that, it is much easier to find a
        shorter proof. Also, remember that clarity is key: write in complete sentences
        with good grammar, but do not include irrelevant information or repeat yourself
        unnecessarily.
        Q2 Propositional Logic:
        Validity and Satisfiability
        For each of the following propositional formulas, determine whether it is valid,
        unsatisfiable, or contingent. If it is valid or unsatisfiable, prove it by drawing
        an appropriate resolution refutation. If it is contingent, demonstrate this with
        two appropriate truth assignments.
        1. ?    (    ?)
        2
        2. (    (    (    )))    (?    ?(?    ?))
        3. ?((    )    )    ( ? )    (    ?)
        4. ( ? )    ((    ) ? ( ? ))
        Hint: If you are unsure, you can use a truth table to help you decide!
        Q3 Predicate Logic: Translation and Seman-
        tics
        Task A
        Translate the following English sentences into formulas of predicate logic. Give
        an appropriate interpretation of any non-logical symbols used. Use the same
        interpretation throughout this question; do not give multiple interpretations.
        1. Iron is heavier than oxygen.
        2. All actinides are radioactive.
        3. Some, but not all, lanthanides are radioactive.
        4. Actinides are heavier than lanthanides.
        5. Both lanthanides and actinides are heavier than iron and oxygen.
        6. At least three isotopes of lanthanides are radioactive, but the only lan-
        thanide without any non-radioactive isotopes is promethium.
        Task B
        By arguing from the semantics of predicate logic, prove that the universe of
        every model of following formula has at least 3 distinct elements. (Resolution
        refutations will receive 0 marks.)
        ??((, )    ?(, ))    ??((, ))
        Q4 Predicate Logic: Red-Black Trees
        The use of function symbols in our notation for predicate logic allows us to
        create a simple representation of binary trees. Namely, let the constant symbol
        represent the root node of the tree, and the unary functions and represent
        the left and right children of a node. The idea is that () is the left child of the
        root node, (()) is the right child of the left child of the root node, and so on.
        With this representation defined, we can now prove statements about trees.
        A red-black tree is a special type of binary tree that can be searched faster,
        in which each node is assigned a colour, either red or black. Let the predicates
        and denote whether a node is red or black respectively. A red-black tree is
        faster to search because it must satisfy some constraints, two of which are:
        3
        1. Every node is red or black, but not both:
        ?((()    ?())    (()    ?())) (1)
        2. A red node does not have a red child:
        ?(()    (?(())    ?(()))) (2)
        Task
        Use resolution to prove that these two conditions entail that a tree consisting
        of a non-black root with a red left child is not a red-black tree.
        Q5 Informal Proof: Palindromes
        Assume the following definitions:
        1. A string is a finite sequence of symbols.
        2. Given a symbol , we write the string consisting of just also as .
        3. Given strings and , we write their concatenation as .
        4. Given a collection of symbols 1,   , , we have the following:
        (a) The expression 1   stands for the string of symbols whose th
        symbol is equal to for all integers from 1 to .
        (b) The reverse of the empty string is the empty string.
        (c) The reverse of a nonempty string 1   of length is the string
        1   where = ?+1 for all positive integers    .
        (d) The expression   1 stands for the reverse of 1  .
        5. A string is a palindrome if and only if it is equal to its reverse.
        Task
        The proof attempt below has problems. In particular, it does not carefully
        argue from these definitions. Identify and describe the problems with the proof.
        Then, give a corrected proof.
        Theorem. Let be a palindrome. Then is also a palindrome.
        Proof (attempt). We have = 1   for some symbols 1,   , where is
        the length of . Since is a palindrome, it is by definition equal to itself under
        reversal, so =   1 and = ?+1 for all positive integers    .
        Therefore = 1    1, and hence there exist symbols 1,   , 2
        such that = 1  2. Since the reverse of 1    1 is itself, it follows
        that is a palindrome, as desired.
        4
        d f g h ie
        b
        a
        c
        Figure 1: Diagram of our 9-segment display. Colour key: horizontal segments
        are blue, vertical segments are green, and diagonal segments are orange.
        Q6 Propositional Logic: Logic on Display
        One common practical application of propositional logic is in representing logic
        circuits. Consider a 9-segment LED display with the segments labelled a through
        i, like the one shown on Figure 1. To display the letter   E  , for example, you
        would turn on LEDs , , , and , and turn the rest off.
        Arrays of similar displays are commonly used to show numbers on digital
        clocks, dishwashers, and other devices. Each LED segment can be turned on or
        off, but in most applications, only a small number of on/off combinations are of
        interest (e.g. displaying a digit in the range 0 C9 only uses 10 combinations). In
        that case, the display can be controlled through a small number of input wires.
        For this question, we are interested in creating a display for eight symbols
        from the proto-science of alchemy. Since we only want eight different symbols
        (see Figure 2), we only need three input wires: , , and .
        Figure 2: Table of symbols, their encodings in terms of , and , and the
        corresponding on/off state of the segments  C.
        So, for example, is represented by = = = 0, and so when all three
        wires are unpowered, we should turn on segments , and ? and turn off the
        other segments. Similarly, is represented by = = 0 and = 1, so when
        wires and are off and the wire is on, we should turn on , and , and
        turn off the other segments.
        5
        Note that each of the display segments  C can be considered a propositional
        function of the variables , , and . For example, segment e is on when the
        input is one of 101, 110, or 111, and is off otherwise. That is, we can capture
        its behavior as the following propositional formula:
        (    ?    )    (       ?)    (       ).
        The logic display must be implemented with logic circuitry. Here we assume
        that only three types of logic gates are available:
        1. An and-gate takes two inputs and produces, as output, the conjunction
        (  ) of the inputs.
        2. An or-gate implements disjunction (  ).
        3. An inverter takes a single input and negates (?) it.
        Task
        Design a logic circuit for each of  C using as few gates as possible. Your answer
        does not need to be optimal1 to receive full marks, but it must improve upon
        the trivial answer. (Incorrect answers will receive 0 marks.)
        We can specify the circuit by writing down the Boolean equations for each
        of the outputs  C. For example, from what we just saw, we can define
        = (    ?    )    (       ?)    (       )
        and thus implement using 10 gates. But the formula (    ?  )    (   )
        is equivalent, so we can in fact implement using 5 gates.
        Moreover, the nine functions might be able to share some circuitry. For
        example, if we have a sub-circuit defined by = ?    , then we can define
        =    (    ?    ?), and also possibly reuse in other definitions. That is,
        we can share sub-circuits among multiple functions. This can allow us to reduce
        the total number of gates. You can define as many   helper   sub-circuits as you
        please, to create the smallest possible solution.
        Submission
        Go to   Assignment 1 (Q6)   on Gradescope, and submit a text file named q6.txt
        consisting of one line per definition. This file will be tested automatically, so it
        is important that you follow the syntax exactly.
        We write ? as - and    as +. We write    as ., or, simpler, we just leave it
        out, so that concatenation of expressions denotes their conjunction. Here is an
        example set of equations (for a different problem):
        # An example of a set of equations in the correct format:
        a = -Q R + Q -R + P -Q -R
        b = u + P (Q + R)
        c = P + -(Q R)
        d = u + P a
        u = -P -Q
        # u is an auxiliary function introduced to simplify b and d
        1Indeed, computing an optimal solution to this problem is extremely difficult!
        6
        Empty lines, and lines that start with   #  , are ignored. Input variables are
        in upper case. Negation binds tighter than conjunction, which in turn binds
        tighter than disjunction.  Note the use of a helper function , allowing and
        to share some circuitry. Also note that we do not allow any feedback loops
        in the circuit. In the example above, depends on , so is not allowed to
        depend, directly or indirectly, on (and indeed it does not).

        請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp






         

        掃一掃在手機打開當前頁
      1. 上一篇:代寫INFO3616、代做Python語言程序
      2. 下一篇:MAST30027代做、Java/C++設計程序代寫
      3. 無相關信息
        合肥生活資訊

        合肥圖文信息
        挖掘機濾芯提升發動機性能
        挖掘機濾芯提升發動機性能
        戴納斯帝壁掛爐全國售后服務電話24小時官網400(全國服務熱線)
        戴納斯帝壁掛爐全國售后服務電話24小時官網
        菲斯曼壁掛爐全國統一400售后維修服務電話24小時服務熱線
        菲斯曼壁掛爐全國統一400售后維修服務電話2
        美的熱水器售后服務技術咨詢電話全國24小時客服熱線
        美的熱水器售后服務技術咨詢電話全國24小時
        海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
        海信羅馬假日洗衣機亮相AWE 復古美學與現代
        合肥機場巴士4號線
        合肥機場巴士4號線
        合肥機場巴士3號線
        合肥機場巴士3號線
        合肥機場巴士2號線
        合肥機場巴士2號線
      4. 幣安app官網下載 短信驗證碼 丁香花影院

        關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

        Copyright © 2024 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
        ICP備06013414號-3 公安備 42010502001045

        主站蜘蛛池模板: 国产主播在线一区| 99精品一区二区免费视频| 亚洲电影一区二区三区| 亚洲韩国精品无码一区二区三区| 久久成人国产精品一区二区| 免费无码毛片一区二区APP| 国产精品免费综合一区视频| 日韩a无吗一区二区三区| 日亚毛片免费乱码不卡一区 | 东京热无码av一区二区| 久久无码人妻一区二区三区| 免费一区二区视频| 97精品一区二区视频在线观看| 精品一区二区三区3d动漫| 91视频一区二区三区| 无码人妻精品一区二区三区久久 | 国产伦精品一区二区三区视频猫咪| 一区二区三区在线|欧| 国产午夜精品一区二区三区漫画 | 国产手机精品一区二区| 亚洲一区综合在线播放| 末成年女A∨片一区二区| 日韩免费视频一区二区| 久久一区二区精品| 国产人妖视频一区二区| 人妻av无码一区二区三区| 无码人妻精品一区二区三18禁| 亚洲日韩国产精品第一页一区| 大伊香蕉精品一区视频在线| 精品成人av一区二区三区| 国产伦精品一区二区三区精品 | 日韩精品无码久久一区二区三| 成人一区二区三区视频在线观看 | 国产剧情一区二区| 中文字幕一区精品| 精品人妻AV一区二区三区| 日韩一区二区在线播放| 精品一区二区三区在线观看l| 亚洲日韩一区二区三区| 无码中文字幕乱码一区| 精品视频一区二区三区在线播放|