合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

        代寫G6017 Program Analysis

        時間:2024-01-14  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



        THE UNIVERSITY OF SUSSEX
        BSc and MComp SECOND YEAR EXAMINATION January 2022 (A1)
        Program Analysis Assessment Period: January 2022 (A1)
        Candidate Number
        G6017
         DO NOT TURN OVER UNTIL INSTRUCTED TO BY THE LEAD INVIGILATOR
        Candidates should answer TWO questions out of THREE.
        If all three questions are attempted only the first two answers will be marked.
        The time allowed is TWO hours. Each question is worth 50 marks.
        At the end of the examination the question paper and/or answer book, used or unused, will be collected from you before you leave the examination room.

        G6017 Program Analysis
        1.
        (a) Precisely specify the conditions under which the following algorithm returns
        true, and then discuss, in detail, the running time of the algorithm. If you think it has different best- and worst-case running times then these should be considered separately, and you should explain the conditions under which best and worst-cases arise.
        You must fully explain your answer and use O,  and  appropriately to receive full marks.
          Algorithm Ex1 ((𝑎1, ... 𝑎𝑛), (𝑏1, ... , 𝑏𝑚))
        𝑘←0
        for 𝑖 ← 1 to 𝑛 do
        𝑗←1
        while 𝑗 ≤ 𝑚 do
        If𝑎 ==𝑏 𝑖𝑗
        𝑘←𝑘+1 𝑗←𝑗+1
        return 𝑘 > 0
         (b) Precisely specify the conditions under which the following algorithm returns true, and then discuss, in detail, the running time of the algorithm. If you think it has different best- and worst-case running times then these should be considered separately, and you should explain the conditions under which best and worst-cases arise.
        You must fully explain your answer and use O,  and  appropriately to receive full marks.
        [10 marks]
         Algorithm Ex2 ((𝑎1, ... 𝑎𝑛), (𝑏1, ... , 𝑏𝑛)) w**2; ← w**5;w**3;w**6;Ү**;
        for𝑖←1to𝑛 do 𝑗←𝑛
        while𝑗>0andw**2; ==w**5;w**3;w**6;Ү**;do If𝑎 ==𝑏
        𝑗←𝑗−1 return w**2;
        𝑖𝑗
        w**2; ← 𝑓𝑎𝑙w**4;Ү**;
         2
        [10 marks]

        (c) Precisely specify the conditions under which the following algorithm returns true, and then discuss, in detail, the running time of the algorithm. If you think it has different best- and worst-case running times then these should be considered separately, and you should explain the conditions under which best and worst-cases arise.
        You must fully explain your answer and use O,  and  appropriately to receive full marks.
         Algorithm Ex3 ((𝑎1, ... 𝑎𝑛), 𝑏)
        w**2;←0
        w**8; ← 𝑓𝑎𝑙w**4;Ү**;
        for 𝑖 ← 1 to 𝑛 − 1 do
        𝑧 ← 𝑎𝑖 + 𝑎𝑖+1 If 𝑧 < 𝑏
        w**2;←w**2;+1
        else
        If w**2; < 0 return w**8;
        w**2;←w**2;−1 w**8; ← w**5;w**3;w**6;Ү**;
         (d) A data pattern analyser is to be built that can detect and count up the number of occurrences of two and three letter same letter sequences in a sequence (e.g. (a,a) or (b,b,b) ). The analyser should stop if it encounters * in the sequence and return the number of occurrences found up to that point in the form of a 2-tuple (#2𝐿Ү**;w**5;w**5;Ү**;w**3;𝑆Ү**;w**2;w**6;Ү**;𝑛𝑐Ү**;w**4;, #3𝐿Ү**;w**5;w**5;Ү**;w**3;𝑆Ү**;w**2;w**6;Ү**;𝑛𝑐Ү**;w**4;). A 3 letter sequence should only count as a 3 letter sequence, not an occurrence of two 2 letter sequences. No letter in the input sequence ever occurs more than 3 times in a row.
        So, for example:
        Input string (a,b,a,b,b,a,a,*)
        (x,x,x,y,y) (p,q,p,z,z,*) (*,a,a)
        (x,x,a,d,*, s,s,s,l)
        2 letter sequences found
        2 1 1 0 1
        3 letter sequences found
        0 1 0 0 0
        [10 marks]
                             3

        Produce a formal statement of this problem, and then write an algorithm to solve the problem using a pseudo code style similar to the one shown in parts (a) to (c). State the bounds on the best and worst case performance of your algorithms using O,  and  appropriately to receive full marks.
        [10 marks]
        (e) A file is protected by a random password consisting of 𝑛 binary bits. All password combinations are equally probable. To access the file we need the correct password. The process of applying the password to the file takes 10ms regardless of the value of 𝑛. Brute force attack is always a viable basic strategy for guessing a password.
        To ensure that the file remains sufficiently secure, we need to ensure that there is no more than a 1% chance over 30 days that the password is guessed by a hacker program utilizing brute force working 24 hours a day, 7 days a week. How many bits should be specified for the password?
        2.
        (a) A student has been asked to put some parcels on a shelf. The parcels all weigh different amounts, and the shelf has a maximum safe loading weight capacity of 100 Kg. The weight of parcels are as follows (in Kg):
        𝒑𝒂𝒓𝒄𝒆𝒍 𝒘𝒆𝒊𝒈𝒉𝒕 (𝑲𝒈)
        18 2 50 ** 4 15 54 65 7 20
        The student has been asked to load the maximum weight possible parcels on the shelf subject to the maximum safe loading weight.
        State two possible approaches for a greedy algorithm solution to solve this problem. In each case, state clearly the result you would get from applying that approach to this problem, stating whether the solution is optimal or not. If
        [10 marks]
                          4

        your answer does not produce an optimal solution, what algorithm could be employed to find one?
        [10 marks]
        (b) One example of a greedy algorithm is the Dijkstra algorithm for finding the lowest cost path through a weighted graph. The diagram below shows two weighted graphs that a student wants to investigate using Dijkstra’s algorithm. In each case the task it to find the lowest cost of reaching every node from v1. Each graph has a single negative weight in it.
        Graph (a) Graph (b)
        One of the graphs will yield a correct analysis of the lowest cost for all vertices, and the other will produce an incorrect analysis. Which of the two graphs will produce the incorrect analysis, and explain why the greedy nature of Dijkstra’s algorithm is responsible for the incorrect analysis. Your answer should include the key concept of an invariant.
        [5 marks]
        (c) The priority queue is a widely used data structure. Priority queues may be implemented using binary heaps and simple linear arrays. For the basic priority queue operations of:
        • Building an initial queue
        • Taking the highest priority item off the queue
        • Adding a new item to the queue
        Compare and contrast the running time complexities (best and worst cases) associated with implementations using binary heaps and simple linear arrays. You may find it helpful to use diagrams to support your answer.
        [10 marks]
                   5

        (d) A recursive algorithm is applied to some data 𝐴 = (𝑎1, ... , 𝑎𝑚) where 𝑚 ≥ 2 and 𝑚 is even. The running time 𝑇 is characterised using the following recurrence equations:
        𝑇(2) = 𝑐 when the size of 𝐴 is 2 𝑇(𝑚) = 𝑇(𝑚 − 2) + 𝑐 otherwise
        Determine the running time complexity of this algorithm. Note that 𝑚 is even and the problem size reduces by 2 for each recursion.
        [10 marks]
        (e) Another recursive algorithm is applied to some data 𝐴 = (𝑎1, ... , 𝑎𝑚) where 𝑚 = 2w**9; (i.e. 2, 4, 8,16 ...) where w**9; is an integer ≥ 1. The running time T is characterised using the following recurrence equations:
        𝑇(1) = 𝑐 when the size of 𝐴 is 1, and 𝑐 is a constant 𝑇(𝑚) = 2𝑇 (𝑚) + 𝑚 otherwise
        2
        Determine the running time complexity of this algorithm. You will find it helpful to recall that:
        w**9;=∞ 1
        ∑2𝑘 →1 w**9;=1
        And
        2𝑙w**0;𝑔2(w**9;) = w**9;
        3.
        [15 marks]
        (a) The subset sum problem can be reliably solved optimally using the dynamic programming algorithm shown below:
           SubsetSum(𝑛, 𝑊)
        Let w**;(0,w**8;) = 0 for each w**8; ∈ {0,...,𝑊} for 𝑖 ← 1 w**5;w**0; 𝑛
        for w**8; ← 0 w**5;w**0; 𝑊 ifw**8;<w**8;𝑖 then
        w**;(𝑖, w**8;) ← w**;(𝑖 − 1, w**8;)
        else
        w**;(𝑖,w**8;)←max(w**8;𝑖 +w**;(𝑖−1,w**8;−w**8;𝑖),w**;(𝑖−1,w**8;))
         6

        Where 𝑛 is the number of requests, 𝑊 is the maximum weight constraint, w**8;𝑖 is the weight associated with request 𝑖, and w**; is the solution space.
        You are given a set of requests and their corresponding weights. The maximum weight constraint 𝑊 is 12.
        𝒊 𝒘𝒊
        11 2** 10 46 53 62
        Copy the following solution space table to your answer book (do not write your answer on the question paper) and complete the table to determine the optimal subset sum.
                               𝒊
        6 5 4 3 2 1 0
        𝒘
        0 1 2 3 4 5 6 7 8 9 10 11 12
        [10 marks]
             (b) The sequence alignment problem may be solved by the following dynamic programming algorithm:
           SequenceAlignment(X, Y):
        Let w**;(𝑖, 0) ← 𝑖 × 𝛾 for each 1 ≤ 𝑖 ≤ 𝑛 Let w**;(0, 𝑗) ← 𝑗 × 𝛾 for each 1 ≤ 𝑗 ≤ 𝑚 For 𝑖 ← 1 w**5;w**0; 𝑛
        For 𝑗 ← 1 w**5;w**0; 𝑚
        w**;(𝑖, 𝑗) ← min [𝛿(w**9; , 𝑦 ) + w**;(𝑖 − 1, 𝑗 − 1),
        𝑖𝑗
        𝛾 + w**;(𝑖, 𝑗 − 1),
        𝛾 + w**;(𝑖 − 1), 𝑗 ]
         7

        Where 𝑋 = (w**9; ,...,w**9; ) and 𝑌 = (𝑦 ,...,𝑦 ) are two sequences to be aligned, 𝛿(w**1;,w**2;) 1𝑛 1𝑚
        is a penalty associated with matching symbol w**1; to w**2;, and 𝛾 is a gap penalty. The sequence alignment algorithm is applied using the following data:
        𝑋 =(𝑎,𝑏,𝑐)
        𝑌 = (𝑎,𝑏,𝑎,𝑏,𝑏)
        𝛾=4
        The delta function is defined for symbols in the alphabet {𝑎, 𝑏, 𝑐} :
        aBc a045 b407 c570
        Generate the problem space matrix w**; and thus determine the optimal alignment between 𝑋 and 𝑌.
        [15 marks] (c) Draw a Minimum Spanning Tree derived from the graph shown below.
        [5 marks]
        (d) The Ford-Fulkerson algorithm is used to determine network flow. The diagram below represents a data network that connects a Data Service Provider (DSP)
                                 8

        connected to w**7;1(w**4;) to a customer connected to w**7;6(w**5;). Each edge represents a single data transmission link.
        The notation w**1;/w**2; indicates a current actual forwards flow w**1; measured in Gb/s in a pipe with a maximum capacity of w**2; also measured in Gb/s.
        At the outset no data is being sent by the DSP to the customer.
        i. Show the residual graph that will be created from the initial empty flow. When drawing the residual graph, show a forward edge with capacity w**9; and a backward edge with flow 𝑦 by annotating the edge w**9;⃗; 𝑦**; .
        [2 marks]
        ii. What is the bottleneck edge of the path (w**4;, w**7;3, w**7;4, w**5;) in the residual graph you have given in answer to part (a) ?
        [2 marks]
        iii. Show the residual graph after incorporating the simple path (w**4;, w**7;3, w**7;4, w**5;) that results from augmenting the flow based on the residual graph you have given in answer to part (a).
        [4 marks]
        iv. Repeat the process outlined above incorporating additionally the simple paths (w**4;, w**7;3, w**7;2, w**7;5, w**5;) , (w**4;, w**7;2, w**7;5, w**7;4, w**5;) and (w**4;, w**7;2, w**7;5, w**5;) showing each residual graph, to determine the maximum flow between w**4; and w**5;, and thus the maximum data bandwidth that can be achieved between the DSP and the customer.
        請加QQ:99515681 或郵箱:99515681@qq.com   WX:codehelp

        掃一掃在手機打開當前頁
      1. 上一篇:代做SIPA U6500、代寫 java,python 程序設計
      2. 下一篇:TEMU FUND海外拼多多是什么?一篇文章告訴你
      3. 無相關信息
        合肥生活資訊

        合肥圖文信息
        挖掘機濾芯提升發動機性能
        挖掘機濾芯提升發動機性能
        戴納斯帝壁掛爐全國售后服務電話24小時官網400(全國服務熱線)
        戴納斯帝壁掛爐全國售后服務電話24小時官網
        菲斯曼壁掛爐全國統一400售后維修服務電話24小時服務熱線
        菲斯曼壁掛爐全國統一400售后維修服務電話2
        美的熱水器售后服務技術咨詢電話全國24小時客服熱線
        美的熱水器售后服務技術咨詢電話全國24小時
        海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
        海信羅馬假日洗衣機亮相AWE 復古美學與現代
        合肥機場巴士4號線
        合肥機場巴士4號線
        合肥機場巴士3號線
        合肥機場巴士3號線
        合肥機場巴士2號線
        合肥機場巴士2號線
      4. 幣安app官網下載 短信驗證碼 丁香花影院

        關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

        Copyright © 2024 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
        ICP備06013414號-3 公安備 42010502001045

        主站蜘蛛池模板: 亚洲熟妇无码一区二区三区| 无码一区二区三区亚洲人妻| 色一情一乱一伦一区二区三欧美 | 国产一区二区三区影院| 3d动漫精品啪啪一区二区中文| 亚洲天堂一区二区三区| 亚拍精品一区二区三区| 国产肥熟女视频一区二区三区 | 福利片福利一区二区三区| 一区二区三区四区视频在线| 亚洲色大成网站www永久一区| 久久久国产精品亚洲一区| 无码一区二区三区在线| 亚洲av区一区二区三| 亚洲AV综合色一区二区三区 | 视频一区二区在线播放| 国产综合精品一区二区三区| 国产日本一区二区三区| 一区二区三区四区电影视频在线观看| 国产成人精品无码一区二区三区| 91无码人妻精品一区二区三区L| 国产在线观看精品一区二区三区91| 久久亚洲中文字幕精品一区四| 中文字幕一区二区三区久久网站| 在线观看中文字幕一区| 久久精品动漫一区二区三区| 国产日韩精品一区二区在线观看播放| 狠狠色婷婷久久一区二区三区| 亚洲第一区二区快射影院| 国产伦精品一区二区三区视频猫咪| 亚洲高清美女一区二区三区| 亚洲国产成人久久综合一区77| 亚洲福利一区二区| 中文字幕不卡一区| 国产精品免费综合一区视频| 91精品一区二区三区在线观看| 日本中文字幕在线视频一区| 国产日本亚洲一区二区三区| 日本免费电影一区二区| 亚洲国产一区二区视频网站| 在线视频精品一区|