合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

        COMP528代寫、代做c/c++編程設計

        時間:2023-12-19  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯


        In this assignment, you are asked to implement 2 algorithms for the Travelling Salesman

        Problem. This document explains the operations in detail, so you do not need previous

        knowledge. You are encouraged to start this as soon as possible. Historically, as the deadline nears, the queue times on Barkla grow as more submissions are tested. You are also

        encouraged to use your spare time in the labs to receive help, and clarify any queries you

        have regarding the assignment.

        1 The Travelling Salesman Problem (TSP)

        The travelling salesman problem is a problem that seeks to answer the following question:

        ‘Given a list of vertices and the distances between each pair of vertices, what is the shortest

        possible route that visits each vertex exactly once and returns to the origin vertex?’.

        (a) A fully connected graph (b) The shortest route around all vertices

        Figure 1: An example of the travelling salesman problem

        The travelling salesman problem is an NP-hard problem, that meaning an exact solution

        cannot be solved in polynomial time. However, there are polynomial solutions that can

        be used which give an approximation of the shortest route between all vertices. In this

        assignment you are asked to implement 2 of these.

        1.1 Terminology

        We will call each point on the graph the vertex. There are 6 vertices in Figure 1.

        We will call each connection between vertices the edge. There are 15 edges in Figure 1.z

        We will call two vertices connected if they have an edge between them.

        The sequence of vertices that are visited is called the tour. The tour for Figure 1(b) is

        (1, 3, 5, 6, 4, 2, 1). Note the tour always starts and ends at the origin vertex.

        A partial tour is a tour that has not yet visited all the vertices.

        202**024 1

        COMP528

        2 The solutions

        2.1 Preparation of Solution

        You are given a number of coordinate files with this format:

        x, y

        4.81263062**6921, 8.3**19930253777

        2.**156816804616, 0.39593575612759

        1.13649642931556, 2.2**59458630845

        4.4**7**99682118, 2.9749120444**06

        9.84251616851393, 9.107****070**

        Figure 2: Format of a coord file

        Each line is a coordinate for a vertex, with the x and y coordinate being separated by a

        comma. You will need to convert this into a distance matrix.

        0.000000 8.177698 7.099481 5.381919 5.0870**

        8.177698 0.000000 2.577029 3.029315 11.138848

        7.099481 2.577029 0.000000 3.426826 11.068045

        5.381919 3.029315 3.426826 0.000000 8.139637

        5.0870** 11.138848 11.068045 8.139637 0.000000

        Figure 3: A distance matrix for Figure 2

        To convert the coordinates to a distance matrix, you will need make use of the euclidean

        distance formula.

        d =

        q

        (xi − xj )

        2 + (yi − yj )

        2

        (1)

        Figure 4: The euclidean distance formula

        Where: d is the distance between 2 vertices vi and vj

        , xi and yi are the coordinates of the

        vertex vi

        , and xj and yj are the coordinates of the vertex vj

        .

        202**024 2

        COMP528

        2.2 Cheapest Insertion

        The cheapest insertion algorithm begins with two connected vertices in a partial tour. Each

        step, it looks for a vertex that hasn’t been visited, and inserts it between two connected

        vertices in the tour, such that the cost of inserting it between the two connected vertices is

        minimal.

        These steps can be followed to implement the cheapest insertion algorithm. Assume that the

        indices i, j, k etc. are vertex labels, unless stated otherwise. In a tiebreak situation, always

        pick the lowest index or indices.

        1. Start off with a vertex vi

        .

        Figure 5: Step 1 of Cheapest Insertion

        2. Find a vertex vj such that the dist(vi

        , vj ) is minimal, and create a partial tour (vi

        , vj

        , vi)

        Figure 6: Step 2 of Cheapest Insertion

        3. Find two connected vertices (vn, vn+1), where n is a position in the partial tour, and

        vk that has not been visited. Insert vk between vn and vn+1 such that dist(vn, vk) +

        dist(vn+1, vk) − dist(vn, vn+1) is minimal.

        202**024 3

        COMP528

        Figure 7: Step 3 of Cheapest Insertion

        4. Repeat step 3 until all vertices have been visited, and are in the tour.

        Figure 8: Step 4 of Cheapest Insertion

        Figure 9: Final step and tour of Cheapest Insertion. Tour Cost = 11

        2.3 Farthest Insertion

        The farthest insertion algorithm begins with two connected vertices in a partial tour. Each

        step, it checks for the farthest vertex not visited from any vertex within the partial tour, and

        then inserts it between two connected vertices in the partial tour where the cost of inserting

        it between the two connected vertices is minimal.

        202**024 4

        COMP528

        These steps can be followed to implement the farthest insertion algorithm. Assume that the

        indices i, j, k etc. are vertex labels unless stated otherwise. In a tiebreak situation, always

        pick the lowest index(indices).

        1. Start off with a vertex vi

        .

        Figure 10: Step 1 of Farthest Insertion

        2. Find a vertex vj such that dist(vi

        , vj ) is maximal, and create a partial tour (vi

        , vj

        , vi).

        Figure 11: Step 2 of Farthest Insertion

        3. For each vertex vn in the partial tour, where n is a position in the partial tour, find an

        unvisited vertex vk such that dist(vn, vk) is maximal.

        Figure 12: Step 3 of Farthest Insertion

        202**024 5

        COMP528

        4. Insert vk between two connected vertices in the partial tour vn and vn+1, where n is

        a position in the partial tour, such that dist(vn, vk) + dist(vn+1, vk) − dist(vn, vn+1) is

        minimal.

        Figure 13: Step 4 of Farthest Insertion

        5. Repeat steps 3 and 4 until all vertices have been visited, and are in the tour.

        Figure 14: Step 3(2) of Farthest Insertion

        Figure 15: Step 4(2) of Farthest Insertion

        202**024 6

        COMP528

        Figure 16: Final step and tour of Farthest Insertion. Tour Cost = 11

        3 Running your programs

        Your program should be able to be ran like so:

        ./<program name >. exe <c o o r d i n a t e f i l e n a m e > <o u t p u t fil e n am e >

        Therefore, your program should accept a coordinate file, and an output file as arguments.

        Note that C considers the first argument as the program executable.

        Both implementations should read a coordinate file, run either cheapest insertion or farthest

        insertion, and write the tour to the output file.

        3.1 Provided Code

        You are provided with code that can read the coordinate input from a file, and write the

        final tour to a file. This is located in the file coordReader.c. You will need to include this

        file when compiling your programs.

        The function readNumOfCoords() takes a filename as a parameter and returns the number

        of coordinates in the given file as an integer.

        The function readCoords() takes the filename and the number of coordinates as parameters,

        and returns the coordinates from a file and stores it in a two-dimensional array of doubles,

        where coords[i ][0] is the x coordinate for the ith coordinate, and coords[i ][1] is the y

        coordinate for the ith coordinate.

        The function writeTourToFile() takes the tour, the tour length, and the output filename

        as parameters, and writes the tour to the given file.

        202**02**

        University of Liverpool Continuous Assessment 1 COMP528

        4 Instructions

        • Implement a serial solution for the cheapest insertion and the farthest insertion. Name

        these: cInsertion.c, fInsertion.c.

        • Implement a parallel solution, using OpenMP, for the cheapest insertion and the farthest insertion. Name these: ompcInsertion.c, ompfInsertion.c.

        • Create a Makefile and call it ”Makefile” which performs as the list states below. Without the Makefile, your code will not grade on CodeGrade (see more in section 5.1).

        – make ci compiles cInsertion.c and coordReader.c into ci.exe with the GNU compiler

        – make fi compiles fInsertion.c and coordReader.c into fi.exe with the GNU compiler

        – make comp compiles ompcInsertion.c and coordReader.c into comp.exe with the

        GNU compiler

        – make fomp compiles ompfInsertion.c and coordReader.c into fomp.exe with the

        GNU compiler

        – make icomp compiles ompcInsertion.c and coordReader.c into icomp.exe with

        the Intel compiler

        – make ifomp compiles ompfInsertion.c and coordReader.c into ifomp.exe the Intel

        compiler.

        • Test each of your parallel solutions using 1, 2, 4, 8, 16, and ** threads, recording

        the time it takes to solve each one. Record the start time after you read from the

        coordinates file, and the end time before you write to the output file. Do all testing

        with the large data file.

        • Plot a speedup plot with the speedup on the y-axis and the number of threads on the

        x-axis for each parallel solution.

        • Plot a parallel efficiency plot with parallel efficiency on the y-axis and the number of

        threads on the x-axis for each parallel solution.

        • Write a report that, for each solution, using no more than 1 page per solution,

        describes: your serial version, and your parallelisation strategy

        • In your report, include: the speedup and parallel efficiency plots, how you conducted

        each measurement and calculation to plot these, and sreenshots of you compiling and

        running your program. These do not contribute to the page limit

        202**024 8

        COMP528

        • Your final submission should be uploaded onto CodeGrade. The files you

        upload should be:

        – Makefile

        – cInsertion.c

        – fInsertion.c

        – ompcInsertion.c

        – ompfInsertion.c

        – report.pdf

        5 Hints

        You can also parallelise the conversion of the coordinates to the distance matrix.

        When declaring arrays, it’s better to use dynamic memory allocation. You can do this by...

        int ∗ o n e d a r ra y = ( int ∗) malloc ( numOfElements ∗ s i z e o f ( int ) ) ;

        For a 2-D array:

        int ∗∗ twod a r ra y = ( int ∗∗) malloc ( numOfElements ∗ s i z e o f ( int ∗ ) ) ;

        for ( int i = 0 ; i < numOfElements ; i ++){

        twod a r ra y [ i ] = ( int ∗) malloc ( numOfElements ∗ s i z e o f ( int ) ) ;

        }

        5.1 Makefile

        You are instructed to use a MakeFile to compile the code in any way you like. An example

        of how to use a MakeFile can be used here:

        {make command } : { t a r g e t f i l e s }

        {compile command}

        c i : c I n s e r t i o n . c coordReader . c

        gcc c I n s e r t i o n . c coordReader . c −o c i . exe −lm

        Now, in the Linux environment, in the same directory as your Makefile, if you type ‘make ci‘,

        the compile command is automatically executed. It is worth noting, the compile command

        must be indented. The target files are the files that must be present for the make command

        to execute.

        202**024 9

        COMP528

        6 Marking scheme

        1 Code that compiles without errors or warnings 15%

        2 Same numerical results for test cases 20%

        3 Speedup plot 10%

        4 Parallel Efficiency Plot 10%

        5 Parallel efficiency up to ** threads 15%

        6 Speed of program 10%

        11 Clean code and comments 10%

        12 Report 10%

        Table 1: Marking scheme

        7 Deadline

        202**024 10

        請加QQ:99515681 或郵箱:99515681@qq.com   WX:codehelp

         

        掃一掃在手機打開當前頁
      1. 上一篇:MA2552代做、代寫Matlab編程語言
      2. 下一篇:代寫選股公式 代做通達信量中尋莊副圖指標
      3. 無相關信息
        合肥生活資訊

        合肥圖文信息
        挖掘機濾芯提升發動機性能
        挖掘機濾芯提升發動機性能
        戴納斯帝壁掛爐全國售后服務電話24小時官網400(全國服務熱線)
        戴納斯帝壁掛爐全國售后服務電話24小時官網
        菲斯曼壁掛爐全國統一400售后維修服務電話24小時服務熱線
        菲斯曼壁掛爐全國統一400售后維修服務電話2
        美的熱水器售后服務技術咨詢電話全國24小時客服熱線
        美的熱水器售后服務技術咨詢電話全國24小時
        海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
        海信羅馬假日洗衣機亮相AWE 復古美學與現代
        合肥機場巴士4號線
        合肥機場巴士4號線
        合肥機場巴士3號線
        合肥機場巴士3號線
        合肥機場巴士2號線
        合肥機場巴士2號線
      4. 幣安app官網下載 短信驗證碼

        關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

        Copyright © 2024 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
        ICP備06013414號-3 公安備 42010502001045

        主站蜘蛛池模板: 精品在线视频一区| 精品在线视频一区| 亚洲一区二区中文| 国产日韩精品一区二区在线观看| 一区二区乱子伦在线播放| 无码人妻精品一区二区三区久久久 | 无码一区二区三区在线观看| 波多野结衣一区二区免费视频| 日韩免费无码视频一区二区三区| 国产熟女一区二区三区四区五区| 立川理惠在线播放一区 | 夜夜添无码试看一区二区三区| 国产主播一区二区三区| 无码人妻一区二区三区av| 亚洲丰满熟女一区二区v| 精品性影院一区二区三区内射 | 一区二区三区四区精品| 中文字幕日韩欧美一区二区三区| 国产精品高清一区二区人妖| 亚洲一区二区三区高清| 久久se精品动漫一区二区三区| 好爽毛片一区二区三区四| 香蕉视频一区二区三区| 人妻少妇AV无码一区二区| 精品视频在线观看你懂的一区| 日韩精品无码人妻一区二区三区| 波多野结衣一区二区三区88| 亚洲片一区二区三区| 国产美女口爆吞精一区二区| 中文字幕国产一区| 亚洲AV成人一区二区三区AV| 久久一区二区明星换脸| 中文字幕精品一区二区| 久久久无码精品人妻一区| 国产伦精品一区二区三区免.费| 八戒久久精品一区二区三区| 国产美女口爆吞精一区二区| 无码日韩精品一区二区三区免费| 麻豆一区二区三区精品视频| 一区二区不卡在线| 精品一区二区三区中文|